Jacobs Geometry
Contents 5 sections

Chapter 16 — Answers

Selected answers for Chapter 16: Non-Euclidean Geometries, transcribed from the book’s appendix. They are meant for checking your work, not for copying — the book prints answers to selected exercises only.

Back to Chapter 16 · Teacher’s answers: Chapter 16 · Complete key: Answers to Exercises PDF · Printed answers: appendices PDF

Lesson 1 (pages 692–695)

1. At the center of the sphere.

2. A radius of the sphere.

3. Two hemispheres.

7. Euclidean geometry.

10. Both geometries.

16. 186°.

18. ∠A = 72°, ∠B = ∠C = 60°; ∠A + ∠B + ∠C = 192°.

22. Yes.

25. Arcs of great circles.

30. Both curves cannot correspond to lines.

31. One.

32. No.

40. No. The sum of the angles of △ABC is greater than 180°.

45. It has three right angles rather than one.

46. It is four times as long.

Lesson 2 (pages 698–700)

1. Its legs.

2. The base angles.

3. The summit.

5. WY and MO.

6. ∠Y and ∠O.

7. Two points determine a line.

9. All right angles are equal.

14. The Ruler Postulate.

16. It is a birectangular quadrilateral whose legs are equal.

17. The summit angles of a Saccheri quadrilateral are equal.

20. An exterior angle of a triangle is greater than either remote interior angle.

23. A Saccheri quadrilateral.

25. The fact that ∠D > ∠C.

26. If the legs of a birectangular quadrilateral are unequal, the summit angles opposite them are unequal in the same order.

29. CD.

31. DM = CM because △ADM ≅ △BCM (SAS).

33. In a plane, two points each equidistant from the endpoints of a line segment determine the perpendicular bisector of the line segment.

38. DA.

40. The line segment connecting the midpoints of the base and summit of a Saccheri quadrilateral is perpendicular to both of them.

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42. In a plane, two lines perpendicular to a third line are parallel.

44. The opposite angles of a parallelogram are equal.

Lesson 3 (pages 704–706)

1. The summit angles of a Saccheri quadrilateral are acute in Lobachevskian geometry.

3. Substitution.

4. A line segment has exactly one midpoint.

6. The line segment connecting the midpoints of the base and summit of a Saccheri quadrilateral is perpendicular to both of them.

7. A quadrilateral that has two sides perpendicular to a third side is birectangular.

9. The Addition Theorem of Inequality.

14. A birectangular quadrilateral whose legs are equal is a Saccheri quadrilateral.

15. The summit of a Saccheri quadrilateral is longer than its base in Lobachevskian geometry.

20. Through a point not on a line, there is more than one line parallel to the line.

28. Birectangular.

34. In Riemannian geometry, the summit of a Saccheri quadrilateral is shorter than its base.

37. They are all half as long.

42. They are congruent squares.

Lesson 4 (pages 709–712)

2. ∠D and ∠E.

4. A Saccheri quadrilateral.

5. The summit angles of a Saccheri quadrilateral are acute in Lobachevskian geometry.

8. Substitution.

10. The sum of the angles of a triangle is less than 180° in Lobachevskian geometry.

14. Corresponding angles of similar triangles are equal.

17. The angles in a linear pair are supplementary.

21. No. The sums of the angles of the two triangles may not be equal.

26. ∠A + ∠B + ∠C > 180°.

27. Riemannian geometry.

31. ∠1 = ∠A + ∠B.

35. △ADE ∼ △ABC (AA).

41. ∠F is a right angle.

42. CFDE is a birectangular quadrilateral (in two different ways).

43. ∠FDE is acute.

46. DE > 2BC.

Review (pages 714–717)

1. A great circle.

2. False.

4. True (because antipodal points are considered to be identical).

7. AD.

12. 360°.

16. ∠ABC = 90°; ∠BCD = 120°; ∠CDA = 90°; ∠DAB = 120°.

17. The quadrilateral is a parallelogram.

19. It is a rhombus.

23. No.

26. Saccheri quadrilaterals.

27. Acute.

32. Substitution.

34. A midsegment of a triangle is less than half as long as the third side.

37. Two points determine a line.

40. The sum of the angles of a triangle is less than 180°.

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